1/(m^2+2)=1/6

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Solution for 1/(m^2+2)=1/6 equation: 



1/(m^2+2)=1/6

We move all terms to the left:

1/(m^2+2)-(1/6)=0



Domain of the equation: (m^2+2)!=0

We move all terms containing m to the left, all other terms to the right

m^2!=-2

m^2!=-2/

m^2!=√-1/0

m!=NAN

m∈R



We add all the numbers together, and all the variables

1/(m^2+2)-(+1/6)=0

We get rid of parentheses

1/(m^2+2)-1/6=0

We calculate fractions

There is no solution for this equation

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